Question

Find the seventh term of the

geometric sequence, given the
first term and common ratio.
a_=1 and r=-2/3
[?]

Answer 1

`T_7 = (64)/(729)`

Explanation:

Given

`a =1`

`r = (2)/(3)`

Required

Determine the 7th term

The nth term of a gp is:

`T_n = a * r^{n-1`

So, we have:

`T_7 = 1 * (2)/(3)^{7-1`

`T_7 = 1 * (2)/(3)^{6`

`T_7 = 1 * (2^6)/(3^6)`

`T_7 = 1 * (64)/(729)`

`T_7 = (64)/(729)`