Question

(2x)(x2) + (2x)(x) + (2x)(–2) + (3)(x2) + (3)(x) + (3)(–2)
Can someone simplify this

Answer 1

`2x^3 + 5x^2 - x - 6`

Explanation:

[NOTE]

I am assuming x2 is
`x^2`, if I am wrong about that then please notify me in the comments

[END NOTE]

The parenthesis are implications that we multiply the numbers within them.

Therefore, multiply.

(2x)(x2)

`2x^3`

(2x)(x)

`2x^2`

`2x^3 + 2x^2`

(2x)(-2)

-4x

`2x^3+2x^2-4x`

(3)(x2)

`3x^2`

`2x^3+2x^2-4x+3x^2`

(3)(x)

3x

`2x^3+2x^2-4x+3x^2+3x`

(3)(-2)

-6

`2x^3+2x^2-4x+3x^2+3x-6`

Now combine like terms, meaning the numbers with the same endings, you cannot add a number with different exponents and adding numbers with and without a variable.

`2x^3 + 5x^2 - x - 6`