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How many moles are in 3.2 x 10^25 atoms of silver?

User Max Worg
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1 Answer

1 vote

Answer:

53 mol Ag

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 3.2 × 10²⁵ atoms Ag

[Solve] moles Ag

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

  1. [DA] Set up:
    \displaystyle 3.2 \cdot 10^(25) \ atoms \ Ag((1 \ mol \ Ag)/(6.022 \cdot 10^(23) \ atoms \ Ag))
  2. [DA] Multiply/Divide [Cancel out units]:
    \displaystyle 53.1385 \ mol \ Ag

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

53.1385 mol Ag ≈ 53 mol Ag

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