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2 Al + Fe2O3 = Al2O3 + 2 Fe

If 0.915 mol Al2O3 is produced, how many grams of iron is produced?

User Mlecz
by
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1 Answer

13 votes
13 votes

Answer:

−7.389056fo3+5.436564f

−l2o3+2l

Step-by-step explanation:

2al+f(2.7182822)o3=al2o3+2f(2.718282)

Step 1: Add -al^2o^3 to both sides.

7.389056fo3+2al+−al2o3=al2o3+5.436564f+−al2o3

−al2o3+7.389056fo3+2al=5.436564f

Step 2: Add -7.389056fo^3 to both sides.

−al2o3+7.389056fo3+2al+−7.389056fo3=5.436564f+−7.389056fo3

−al2o3+0fo3+2al=−7.389056fo3+5.436564f

Step 3: Factor out variable a.

a(−l2o3+2l)=−7.389056fo3+5.436564f

Step 4: Divide both sides by -l^2o^3+2l.

a(−l2o3+2l)

−l2o3+2l

=

−7.389056fo3+5.436564f

−l2o3+2l

a=

−7.389056fo3+5.436564f

−l2o3+2l

User Frank Osterfeld
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3.6k points