Answer:
The velocity stays the same
Step-by-step explanation:
Given data
Mass M1= 5kg
U1=2m/s
V1=???
Mass M2= 10kg
V2= 0m/s
U2=0m/s
We know that the law of conservation of linear momentum is expressed as
M1U1+M2U2= M1V1+M2V2
substitute
5*2+10*0=5*V1+10*0
10=5V1
V1= 10/5
V1= 2 m/s
The 5kg mass will bounce back with a velocity of 2m/s
Hence the velocity stays the same