Question

What is the number of moles of H2 produced when 23 g of sodium react with water according to the equation 2Na(s) + 2H2O(l)  2NaOH(aq) + H2(g)

Answer 1

0.5 mole of H₂.

Step-by-step explanation:

We'll begin by calculating the number of mole in 23 g of Na. This can be obtained as follow:

Mass of Na = 23 g

Molar mass of Na = 23 g/mol

Mole of Na =?

Mole = mass / Molar mass

Mole of Na = 23 / 23

Mole of Na = 1 mole

Next, the balanced equation for the reaction.

2Na + 2H₂O —> 2NaOH + H₂

From the balanced equation above,

2 moles of Na reacted to produce 1 mole H₂.

Finally, we shall determine the number of mole of H₂ produced by the reaction of 23 g (i.e 1 mole) of Na. This can be obtained as follow:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole H₂.

Therefore, 1 mole of Na will react to produce = (1 × 1) / 2 = 0.5 mole of H₂.

Thus, 0.5 mole of H₂ is obtained from the reaction.