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In ijk,i=170 inches,j=119 and k=42.find the area of ijk,to the nearest square inch

User Drobison
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1 Answer

22 votes
22 votes

9514 1404 393

Answer:

25,975 in²

Explanation:

Since your j+k < i, we assume that not all of these dimensions are side lengths. If we assume ...

i = 170 in

J = 119°

K = 42°

Then we can find side j using the law of sines.

I = 180° -119° -42° = 19°

Then the law of sines tells us ...

j/sin(J) = i/sin(I)

j = i·sin(J)/sin(I) = (170 in)sin(119°)/sin(19°) = 456.695

Then the area of the triangle is ...

A = (1/2)(i·j·sin(K)) = (1/2)(170 in)(456.695 in)sin(42°) ≈ 25,975.03 in²

The area of triangle IJK is about 25,975 square inches.

In ijk,i=170 inches,j=119 and k=42.find the area of ijk,to the nearest square inch-example-1
User Cavallo
by
3.6k points
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