A 52-in TV measures 52 inches along its diagonal (corner to corner measure). If that TV is 33.6 inches high, how wide is it?

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LiamK asked Dec 3, 2022

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A 52-in TV measures 52 inches along its diagonal (corner to corner measure). If that TV is 33.6 inches high, how wide is it?

Mathematics
college

LiamK asked Dec 3, 2022

by LiamK

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27 votes

Answer:

1575.04

Explanation:

Using Pythagoras theorem,

a^2+b^2=C^2

52^2-33.6^2=1575.04

Joshua Augustinus answered Dec 6, 2022

by Joshua Augustinus

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11 votes

Explanation:

Use Pythagoras' theorem

52² = 33.6² + x²

solve for x

DniHze answered Dec 9, 2022

by DniHze

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