Question

Question - Complete and balance the following chemical equations:

C8H18 + O2 --->

When you complete and balance the specific equation, give the following information:

State which type of chemical reaction this is.
Explain how you know which type of chemical reaction it is.
List the amount of each element you have when the equation is unbalanced. E.g. there is one mole of calcium on the reactants side.
Give the balanced chemical equation.
List the amount of each element you have when the equation is balanced.
The order of the elements that you balanced the equation with.
Explain how you know which coefficient to use for the specific compound.


Your Answer:

Answer 1

To balance the equation C8H18 + O2 --> CO2 + H2O, you can start by balancing the carbon and hydrogen atoms. There are 8 carbon atoms and 18 hydrogen atoms on the left side of the equation, and you can balance them by placing the coefficients 8 and 9 in front of CO2 and H2O, respectively. Next, you can balance the oxygen atoms by placing the coefficient 16 in front of O2. This gives you the balanced equation: C8H18 + 16O2 --> 8CO2 + 9H2O.

Step-by-step explanation:

A chemical equation in which the same number and types of atoms appear on each side of the arrow is called balanced. In order to balance an equation, insert coefficients in front of the appropriate reactants or products until there are the same number and types of atoms on both sides of the arrow.

When balancing a chemical equation, it is important to remember those elements that naturally occur as diatomic molecules, such as oxygen (O2) and hydrogen (H2). These elements should be written as diatomic molecules in the equation.

To balance the equation C8H18 + O2 --> CO2 + H2O, we can start by balancing the carbon and hydrogen atoms. There are 8 carbon atoms and 18 hydrogen atoms on the left side of the equation, and we can balance them by placing the coefficients 8 and 9 in front of CO2 and H2O, respectively.

Next, we can balance the oxygen atoms by placing the coefficient 16 in front of O2. This gives us the balanced equation: C8H18 + 16O2 --> 8CO2 + 9H2O.

Answer 2

2C8H18 + 25O2 -> 16CO2 + 18H2O

(16C, 36H, 50O)

H2O requires 2H per H2O, Meaning that you'd have 9H2O's from 1C8H18, but you still need that O2 for the CO2 and because the reactant side has 8C (within C8H18) You'd have to times the amount of required O2 from CO2 by 8. Even then you still don't have enough for both CO2 and H2O so you'll have to multiply MORE causing a bigger chain reaction resulting in 2C8H18 + 25O2 -> 16CO2 + 18H2O