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Pb(NO3)2(aq)+2KCI(aq)------- PbCl2(s)+2KNO2 (aq). how many grams of PbCl2 solution will react with a 0.46L of a 0.101m KCI solution​

User Jawher
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25 votes
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hi so can help me with something

User GRme
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Answer:

6.46g of PbCl2 are produced

Step-by-step explanation:

The PbCl2 will not react, is a product of the reaction. The question must be say how many grams of PbCl2 will be produced

Based on the chemical reaction:

Pb(NO3)2(aq)+2KCI(aq) → PbCl2(s)+2KNO2 (aq)

1 mole of PbCl2 is produced when 2 moles of KCl are reacting.

To solve this question we must find the moles of KCl that will react. With these moles we can find the moles of PbCl2 and the grams produced using its molar mass:

Moles KCl:

0.46L * (0.101moles / L) = 0.04646 moles KCl

Moles PbCl2:

0.04646 moles KCl * (1mol PbCl2 / 2mol KCl) =

0.02323 moles of PbCl2 are produced

Mass -Molar mass PbCl2: 278.106g/mol-

0.02323 moles * (278.106g / mol) =

6.46g of PbCl2 are produced

User Bmdelacruz
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