Answer:
first evening, 10 calls, second evening 80 calls, third evening, 20 calls.
Explanation:
if the number of calls received during the first evening is X, then the number of calls received during the third evening is X+10 as the third evening received 10 more calls than first evening. The second evening received 4 times of third so 4X+10. Add them up together and put them equal to 110.
X+10+X+4X+40=110
6X+50=110
6X=110-50
6X=60
X=10
First evening, 10 calls,
second evening 80 calls; 4X+40, 4(10)+40=80
third evening 20 calls; X+10, (10)+10=20