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pb(No3)2(aq) +2KCI(aq)---PbCl2(s)+KNO2(aq). how many grams of PbCl2 solution will react with a 0.46 L of a 0.101m KCI solution​

User Willcwf
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2 Answers

7 votes
7 votes

Answer:

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User Jonathan Striebel
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19 votes
19 votes

Answer:

6.3986g

Step-by-step explanation:

The balanced chemical equation of this reaction is as follows:

Pb(NO3)2(aq) + 2KCl (aq) → PbCl2(s) + 2KNO3(aq)

In this equation, 2 moles of KCl solution will produce 1 mole of PbCl2.

To calculate the number of moles of PbCl2 produced, we use the formula:

Molarity = number of moles (n) ÷ volume (V)

0.101 = n/0.46

n = 0.046mol of KCl

If 2 moles of KCl solution will produce 1 mole of PbCl2

Then, 0.046mol of KCl will be react to produce (0.046 × 1/2) of PbCl2

0.046 × 1/2 = 0.023mol of PbCl2

To find the mass of PbCl2 using mole = mass ÷ molar mass

Molar mass of PbCl2 = 207.2 + 35.5(2)

= 207.2 + 71

= 278.2g/mol

0.023 = mass/278.2

mass = 6.3986g

User Ahmad F
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