130k views
3 votes
Write the equation in standard form for the circle that has a diameter with endpoints (-4,2) and (–4,–14).

User Ha Sh
by
7.9k points

1 Answer

5 votes

Answer:

(x + 4)² + (y + 6)² = 64

Explanation:

The standard form of equation of a circle is given as;

(x - a)² + (y - b)² = r²

Where;

a and b are the centre coordinates and r is the radius.

First of all, let's Calculate the midpoint coordinates.

This gives;

((-4 + (-4))/2), (2 + (-14))/2)

This is now (-4, -6)

Distance of radius is;

r = √((-4 - (-4))² + (-6 - 2)²)

r = 8

Equation of circle is now;

(x - (-4))² + (y - (-6))² = 8²

This gives;

(x + 4)² + (y + 6)² = 64

User Coolmine
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories