(8x^2+3xy-20y^2)-(-4x^2+3xy+20y^2)

asked Jul 14, 2022 94.9k views

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Explanation:

(8x² + 3xy -20y²)-(-4x²+3xy+20y²)

= 8x² + 3xy -20y² + 4x² -3xy - 20y²

= 8x² + 4x² + 3xy - 3xy -20y² -20y²

= 12x² - 40y²

Rdaniels answered Jul 18, 2022

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