Question

If a> 1 then prove that a^2>1

Answer 1

Explanation:

a² = a × a

a > 1

a² = (1+d) × (1+d) = 1² + 2d + d²

with d > 0

since d > 0, then so is 2d and also d².

so, a² is the sum of 1² = 1 and something greater than 0.

so, a² > 1