Question

A balloon has a volume of 105 Lif the temperature is 20 °C. If the temperature is -55°C,

what will be the volume of the volume?

Answer 1

78.12 L

Step-by-step explanation:

Given that,

Initial volume, V₁ = 105 L

Initial temperature, T₁ = 20°C = 20+273 = 293 K

New temperature, T₂ = -55 °C = 218 K

We need to find the new volume of the balloon. The relation between the volume and the temperature is given by :

`(V_1)/(T_1)=(V_2)/(T_2)`

Where

V₂ is the new volume

`V_2=(V_1T_2)/(T_1)\\\\V_2=(105* 218)/(293)\\\\V_2=78.12\ L`

So, the new volume is 78.12 L.