Question

Which quadratic function has one real solution

0=2(x+7)(x-5)
0=2/3(x-3)(x-3)
0=2.4(x-2)(x+2)
0=1/2(x-2)(x-1)

Answer 1

Answer:
`0=(2)/(3)(x-3)(x-3)`

Explanation:

1. The roots are
   `-7` and
   `5`.
2. There is one only distinct root, which is
   `3`.
3. The roots are
   `\pm 2`.
4. The roots are
   `1` and
   `2`.