Question

How many grams of nitrogen trihydride would be produced if 9 moles of

hydrogen were used with excess nitrogen?

Answer 1

Reaction:

N₂ (g) + 3 H₂ (g) ---> 2 NH₃ (g)

mol NH₃ = H₂ (limited reactant) :

`\tt (2)/(3)* 9=6~moles`

grams: mol x Mr NH₃ (17 g/mol):

`\tt = 6* 17=102~g`