Question

A long -jumper had a take-off of 9.5m/s. What is the maximum possible horizontal distance the man can jump​

Answer 1

4.5125m

Step-by-step explanation:

Initial Velocity(U)=9.5m/s

Maximum Horizontal Distance (i.e maximum height) = ?

V^2=U^2-2gH (negative because the motion is against gravity i.e g is negative)

• where V=0m/s and g=10m/s^2

0^2=9.5^2-(2×10×H)

0=90.25-20H

20H=90.25

H=90.25/20=4.5125m