Question

A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 sec?

Answer 1

v = 50 ms^1

Step-by-step explanation:

We know:

F = 10N

m = 2kg

t = 10 sec

F=ma

10 = 2*a

5=a

a = 5 ms^2

Now,

a=v/t

5 = v/10

50 = v

v = 50 ms^1