125,647 views
21 votes
21 votes
Two kilograms of air in a piston-cylinder assembly undergoes an isothermal

process from an initial state of 200 K, 300 kPa to 600 kPa.
How much work is done during the process, in kj?​

User Abolfazl
by
3.1k points

1 Answer

11 votes
11 votes

Answer:

a) 0.39795 kJ/K

b) 79.589.37 kJ

Explanation:

m = Mass of air = 2 kg

Temperature = 200 K

P₁ = Initial pressure = 300 kPa

P₂ = Final pressure = 600 kPa

R = mass-specific gas constant for air = 287.058 J/kgK

a) For isentropic process

∴ Entropy is generated in the process is 0.39795 kJ/K

b)

∴ Amount of lost work is 79.589.37 kJ

User Cracker
by
3.3k points