Answer:
y=-5.5x-52
Explanation:
Your input: find the equation of a line given two points P = (-10 , 3) and Q = (-8 , -8). The slope of a line passing through the two pointsP=(x1,y1) and Q=(x2,y2) is given byWe have that x1 = -10 , y1 = 3, x2 = -8 , y2 = -8Step 2:Plug the given values into the formula for slope:Step 3:Now, the y-intercept is b=y1−m⋅x1 (or b=y2−m⋅x2, the result is the same).b = 3 - (-5.5) ⋅ (-10) = -52Step 4:Finally, the equation of the line can be written in the form y=mx+b.y = -5.5x -52The equation of the line in the slope-intercept form is:y = -5.5x -52The equation of the line in the point-slope form is:y - (3) = -5.5 ⋅ ( x - (-10))The equation of the line in the point-slope form is:y - (-8) = -5.5 ⋅ ( x - (-8))The general equation of the line is:-5.5x - y -52 = 0