Answer:
ΔL = L * 1.9E-5 * ΔT
ΔA = A * 2 * 1.9E-5 * ΔT
ΔA = .6 * 3.8E-5 * 1.5E4 mm = .34 mm
New area = 600.34 mm
Note: (L + ΔL)^2 = L + 2 L ΔL + ΔL^2 where ΔL is a small quantity
(L + ΔL)^2 - L^2 = 2 L ΔL = L ΔA
where the coefficient of area expansivity is twice that of linear expansivity