Question

a thin wire 7.0m long has a charge of 1 nC. Find the electric field strength 2.0 mm from the edge of the wire along the axis of the wire.

Answer 1

1400

Step-by-step explanation:

because when the 70m long x20m lone will give u 1400 then u time it with 1 that will give u 1400

Answer 2

To find the electric field strength at a distance of 2.0 mm from the edge of the wire, we can use the equation for electric field:

E = k * Q / r^2

where E is the electric field strength, k is the Coulomb constant (8.99 x 10^9 N * m^2 / C^2), Q is the charge on the wire (1 nC), and r is the distance from the edge of the wire (2.0 mm).

Plugging these values into the equation, we get:

E = (8.99 x 10^9 N * m^2 / C^2) * (1 x 10^-9 C) / (2.0 x 10^-3 m)^2

This simplifies to:

E = 2.24 x 10^5 N/C

So the electric field strength at a distance of 2.0 mm from the edge of the wire is approximately 2.24 x 10^5 N/C.