208k views
3 votes
wa Find the equation of the line that contains the given point and is perpendicular to the given line. Write the equation in slope-intercept form, if possible. (12,4), y=-3x-9​

User Harry Lime
by
8.4k points

2 Answers

6 votes
To find the equation of the line that contains the given point (12, 4) and is perpendicular to the given line y = -3x - 9, we can use the slope-intercept form of a line, which is y = mx + b, where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).

We are given that the line we are trying to find is perpendicular to the line y = -3x - 9. This means that the slope of our line is the negative reciprocal of the slope of the given line, which is -(-3) = 3.

Since the point (12, 4) lies on the line, we can use the point-slope formula to find the equation of the line. The point-slope formula is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope of the line.

Substituting the values into the point-slope formula, we get:

y - 4 = 3(x - 12)

Simplifying, we get:

y = 3x - 36

This is the equation of the line in slope-intercept form. Therefore, the equation of the line that contains the point (12, 4) and is perpendicular to the line y = -3x - 9 is y = 3x - 36.
User Tianxiang Xiong
by
8.2k points
6 votes

Answer:

Explanation:

y = 3x + 2

User Amit Prajapati
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories