Answer:
To solve this problem, we can set up a system of two equations to represent the given information:Let A be the cost of an apple and B be the cost of a banana.Then the first equation is: 4A + 3B = 4.48
The second equation is: 3A + 4B = 4.76To find the values of A and B, we can solve this system of equations using substitution or elimination.Using substitution, we can solve for A in the first equation and substitute that expression into the second equation:4A + 3B = 4.48
A = (4.48 - 3B)/4Substituting this expression for A into the second equation gives:3((4.48 - 3B)/4) + 4B = 4.76
3(4.48 - 3B) + 4B = 4.76
13.44 - 9B + 4B = 4.76
4.44 - 5B = 4.76
-5B = -0.32
B = 0.064Now that we have found the value of B, we can substitute it back into the first equation to find the value of A:4A + 3(0.064) = 4.48
4A + 0.192 = 4.48
4A = 4.288
A = 1.072Therefore, the cost of an apple is £1.072 and the cost of a banana is £0.064.
Explanation: