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(x.y)-(x+6. y - 3 )

(x, y) -(x-6.y-3)

(x, y) -(x+6.y+3)

(x, y) -(x-6.y+3)

Please help (x.y)-(x+6. y - 3 ) (x, y) -(x-6.y-3) (x, y) -(x+6.y+3) (x, y) -(x-6.y-example-1
User AYETY
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1 Answer

5 votes

Answer:

A) (x, y) → (x + 6, y - 3)

Step-by-step explanation:

From inspection of the given diagram, the vertices of the pre-image ΔPQR are:

  • P = (-1, 4)
  • Q = (-1, 2)
  • R = (3, 1)

The vertices of the image ΔP'Q'R' are:

  • P' = (5, 1)
  • Q' = (5, -1)
  • R' = (9, -2)

To find the translations that map ΔPQR onto ΔP'Q'R' find the differences between the x-values and y-values of the corresponding vertices.


\implies \sf x_(P')-x_(P)=5-(-1)=6


\implies \sf y_(P')-y_(P)=1-4=-3

Therefore, the translations are:

  • x + 6 and y - 3

Therefore, the mapping rule that maps ΔPQR onto ΔP'Q'R'is:

  • (x, y) → (x + 6, y - 3)
User Jakub Holovsky
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