Question

5) When light of frequency 5.4 x 10¹ Hz is incident on

emitted electrons is 1.2 x 1019J. Calculate the
a metal surface, the maximum energy of the
minimum frequency of radiation for which
electrons can be emitted. [h=6.6x1034Js]

Answer 1

The minimum frequency of radiation required for electrons to be emitted from a metal surface when light is incident upon it is calculated using the photoelectric effect equation E = hf, resulting in a frequency of 1.82 x 1052 Hz.

Step-by-step explanation:

The student's question is about finding the minimum frequency of radiation for which electrons can be emitted from a metal surface when light is incident on it. This relates to the photoelectric effect, a phenomenon explained by Einstein using quantum theory. To solve this, we need to use the equation that relates the energy of an emitted electron to the frequency of the incident light:

E = hf

Where 'E' is the energy of the emitted electrons, 'h' is Planck's constant (6.6 x 10-34 Js), and 'f' is the frequency of the incident light. Given that the maximum energy of the emitted electrons is 1.2 x 1019 J and we want to find the frequency 'f', we simply rearrange the formula to solve for 'f':

f = E / h

Substituting the given 'E' and 'h' values:

f = (1.2 x 1019 J) / (6.6 x 10-34 Js)

After calculating, we get:

f = 1.82 x 1052 Hz

This is the minimum frequency required for electrons to be emitted from the metal surface in question.

Answer 2

To calculate the minimum frequency of radiation for which electrons can be emitted, we need to use the equation E = hf, where E is the maximum energy of the emitted electrons, h is the Planck constant, and f is the frequency of the radiation. Substituting the given values, we get:

E = hf

1.2 x 10^19 J = (6.6 x 10^34 Js)(f)

f = 1.8 x 10^15 Hz

Therefore, the minimum frequency of radiation for which electrons can be emitted is 1.8 x 10^15 Hz.

Step-by-step explanation:

To calculate the minimum frequency of radiation for which electrons can be emitted, we need to use the equation E = hf, where E is the maximum energy of the emitted electrons, h is the Planck constant (6.6 x 10^34 Js), and f is the frequency of the incident radiation.

Plugging in the given values, we have E = (6.6 x 10^34 Js)(5.4 x 10^14 Hz). Solving for f, we get f = E/h = (1.2 x 10^19 J)/(6.6 x 10^34 Js) = 1.8 x 10^-15 Hz. This is the minimum frequency of radiation for which electrons can be emitted from the metal surface.