Step-by-step explanation:
Work out the number of moles in
100.00
grams of the oxide.
For nitrogen: The atomic mass of
N
is
14.0067
, and we have
36.84
g N
:
36.84
g N
14.0067
g N/mol N
=
2.630
mol N
For oxygen: The atomic mass of
O
is
15.9994
, and we have
100.00
−
36.84
=
63.16
g O
:
63.16
g N
15.9994
g N/mol N
=
3.948
mol N
Now the ratio
3.958
2.630
is very close to
1.5
=
3
2
. So we conclude that the gas has three moles
O
to two moles
N
making the empirical formula
N
2
O
3
.