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I'm struggling with this differential rate law equation. The question and context are in the image. Thank you.

I'm struggling with this differential rate law equation. The question and context-example-1

1 Answer

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Answer:

3.Rate law=k[BH3]^1×[NH3]^1

Step-by-step explanation:

first and 2nd trial comparison

when NH3 is halved, the rate is halved and therefore the exponent is 1

2nd and third trial comparison

0.125 to 0.100

which will effect the initial rate by ×100/125

the initial rate would be 0.0852×200/250

will be 0.0682

therefore the exponent for BF is 1

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