Explanation:
this is a college level question ?
you are in college and don't know how to divide ?
I strongly feel you must have left something out here, especially also your phrasing does not make it clear if 143 is to be divided by 65, or 65 by 143.
if 143 / 65
we make a group of digits starting on the left. we take 1, then combine it with 4, giving us 14.
is 65 at least once contained in 14 ? no.
so, we combine it with the next digit 3.
is 65 at least once contained in 143 ? yes.
but how often fits 65 into 143 ? only once ?
1×65 = 65, the difference to 143 is 143-65 = 78.
but 65 fits also into 78. so, it fits 2 times into 143 :
143 ÷ 65 = 2
now, we multiply 65 by the found factor 2 and subtract this from the current base number 143
143 ÷ 65 = 2
- 130
-----------
13
so, we have a remainder of 13.
so, we keep on going. since we don't have any given digits anymore, we keep assuming 0s on the right hand side. but they are now after the decimal point, so, our result gets a decimal point too :
143 ÷ 65 = 2.
- 130
-----------
130
and now our new number to divide is 130. how often does 65 fit into 130 ? we have seen before, 65×2 = 130. so it fits 2 times :
143 ÷ 65 = 2.2
- 130
-----------
130
we continue as before by multiplying 65 by the find factor and subtracting this from the current reference :
143 ÷ 65 = 2.2
- 130
-----------
130
- 130
------------
0
we have 0 remainder, and that means we are finished.
143/65 = 2.2
now, if we needed the other direction
65 ÷ 143 =
we start the same way. 6 is combined with 5.
but 143 does not fit into 65. so we need to keep going with the invisible 0s. and we are crossing already the decimal point, so we get
65 ÷ 143 = 0.
650
so, how often does 143 fit into 650 ?
5 times ? 5×143 = 715. the is too big. so, 4 times it is.
and we multiply 143 by the newly found factor 4 and subtract the result from our reference :
65 ÷ 143 = 0.4
650
- 572
------------
78
and we keep on going by combining the remainder with the next invisible 0.
65 ÷ 143 = 0.4
650
- 572
------------
780
how often does 143 fit into 780 ? we know from before, 5×143 = 715, so, 5 times it is.
and we repeat the procedure (multiply 143 by the new found factor and subtract the result)
65 ÷ 143 = 0.45
650
- 572
------------
780
- 715
------------
65
and we keep on going with the next invisible 0, find the next factor, multiply and subtract, ...
65 ÷ 143 = 0.454
650
- 572
------------
780
- 715
------------
650
- 572
‐--------------
78
and the next time
65 ÷ 143 = 0.4545
650
- 572
------------
780
- 715
------------
650
- 572
‐--------------
780
- 715
---------------
65
do you notice something ? yes, this pattern will now continue forever.
we will never fully finish the division, as we will never reach 0 remainder, and 4 and 5 will continue alternately to be the next factor and the next factor and ...
so, we can say
65/143 = 0.45454545454545...