Question

Which is the solution of the quadratic equation (4y – 3)^
2 = 72?

Answer 1

`(4y-3)^2=72\implies \pm√((4y-3)^2)=\pm√(72)\implies 4y-3=\pm√(72) \\\\\\ 4y=\pm√(72)+3\implies y=\cfrac{\pm√(72)+3}{4}\implies y= \begin{cases} (√(72)+3)/(4)\\\\ (-√(72)+3)/(4) \end{cases}`