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Consider the following method:

public static void mix(String word, String letter)

{

int counter = 0;

while(word. IndexOf(letter) > 0)

{

if(word. Substring(counter,counter + 1). Equals(letter))

{

word = word. Substring(0, counter) + "0"

+ word. Substring(counter +2, word. Length());

}

counter++;

}

System. Out. Println(word);

}


What value word would be printed as a result of the call mix("Hippopotamus", "p")?


Hippopotamus



Hi0o0tamus



Hi00o0otamus



Hiootamus



Hi0po0otamus

1 Answer

5 votes

Answer:

The value that would be printed as a result of the call mix("Hippopotamus", "p") is Hi0po0otamus.

The method starts by initializing the counter variable to 0. It then enters a while loop that continues as long as the IndexOf method returns a value greater than 0. This means that the loop will continue as long as the letter "p" is found in the word.

Inside the loop, the code checks if the character at the current position in the word (determined by the counter variable) is equal to the letter "p". If it is, it replaces that character with the character "0" and updates the value of the word variable. If it is not, the counter variable is incremented and the loop continues.

Since the word "Hippopotamus" contains two occurrences of the letter "p", the loop will run twice and replace both occurrences with "0", resulting in the output Hi0po0otamus.

Step-by-step explanation:

User Npretto
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