Question

Approximately how many formula units of NaCl are in 116.88g of table salt (NaCl), knowing that the molar mass of NaCl is 58.44g/mol?

Answer 1

There are 1.2044 × 10²⁴ formula units of NaCl in 116.88 g of table salt (NaCl)

Step-by-step explanation:

A formula unit is an empirical formula of the smallest collection or number of atoms in an ionic or covalent combination from which a compounds formula can be established and which are used to represent the compound stoichiometrically

Sodium chloride is an ionic compound and is represented by the formula unit NaCl as it composed of ions and is not therefoe represented by a molecular formula

The given mass of the table salt, NaCl = 116.88 g

The molar mass of NaCl = 58.44 g/mol = The mass of 1 mole of NaCl

1 mole of NaCl contains one Avogadro's number or 6.022 × 10²³ formula units of NaCl,

∴ 58.44 g of NaCl contains 6.022 × 10²³ formula units of NaCl

116.88 g of NaCl will have (116.88/58.44) × 6.022 × 10²³ = 1.2044 × 10²⁴ formula units of NaCl

The number of formula units of NaCl in 116.88 g of table salt (NaCl) = 1.2044 × 10²⁴ formula units of NaCl.

Answer 2

116.88g of table salt (NaCl) contains two formula units

Step-by-step explanation:

Now,

We know that 1 formula unit of sodium chloride has a molar mass of 58.44g/mol

Hence;

Mass of 1 formula unit = 58.44g

Mass of x formula units = 116.88g

x = 116.88g * 1 formula unit/58.44g

x = 2 formula units

Therefore;

116.88g of table salt (NaCl) contains two formula units