Answer:
approximately 1.74 million meters per second.
Step-by-step explanation:
The maximum kinetic energy of a photoelectron emitted from a surface is equal to the work function of the surface, which is the minimum amount of energy required to remove an electron from the surface.
In this case, the work function of the nickel surface is 5.1 eV, so the maximum kinetic energy of the photoelectron is also 5.1 eV.
The kinetic energy of a moving particle is related to its speed by the equation:
KE = (1/2) * m * v^2
where KE is the kinetic energy, m is the mass of the particle, and v is the speed.
If we solve this equation for v and substitute in the values given in the question, we can find the maximum speed of the photoelectron:
v = sqrt(2 * KE / m)
v = sqrt(2 * 5.1 eV / 9.109e-31 kg)
v = 1.74e6 m/s
Thus, the maximum speed of the photoelectron emitted from the nickel surface is approximately 1.74 million meters per second.