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295 mL of a 1. 00 M ammonium chloride (NH4CI) solution is diluted with 2. 25 L of water. What is the new concentration in molarity?

User Fons
by
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1 Answer

3 votes

Answer:

Step-by-step explanation:

To find the new concentration of the solution, we need to use the dilution formula:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

In this case, the initial concentration is 1.00 M and the initial volume is 295 mL, while the final volume is 2.25 L. We can plug these values into the dilution formula to solve for the final concentration:

C2 = (C1V1)/V2

= (1.00 M)(295 mL)/(2.25 L)

= 0.131 M

Therefore, the new concentration of the solution is 0.131 M.

User Athar
by
8.5k points

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