Question

How much energy is required to change a 0.04 kg ice cube from ice at –10°C to water at 80°C?

Answer 1

3.2kcal

Step-by-step explanation:

ΔQ = 0.04 kg*(0.49 kcal/(kgoC))*10 oC = 0.196 kcal. ΔQ = 0.04 kg*80 kcal/kg = 3.2 kcal.