Question

Solving systems by substitution x+y=10
4x-3y=12

Answer 1

x = 6

y = 4

Explanation:

x+y=10

4x-3y=12

Times the first equation by three and solve

3x + 3y = 30

4x - 3y = 12

7x = 42

x = 6

Then put 6 back in to solve for y

4(6) - 3y = 12

24 - 3y = 12

-3y = -12

y = 4

Let's check

6 + 4 = 10

10 = 10

So, my answer is correct!