31.4k views
4 votes
Solve the following system of equations.3x+2y-5y=0 x=y+10

User Emin Kotan
by
3.8k points

1 Answer

2 votes

Answer:

No solutions

Explanation:

3x+2y-5y=0

3x-3y=0

x=y+10

3(y+10)-3y=0 ==> plugin y+10 for x

3*y + 3*10 - 3y = 0 ==> distribute 3 to y and 10

3y + 30 - 3y = 0

3y - 3y + 30 = 0

30
\\eq 0

3(y+10)-3y
\\eq 0

3(y+10)-3y
\\eq 3x-3y ==> 3x-3y=0

Hence, there are no solutions.

User Cnluzon
by
4.4k points