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Find the number of line segments with one endpoint A(20,24) and another endpoint on x -axis with integer coordinates, which have a common point with the line segment PQ, where P(0,4), Q(40,4)

User Herzult
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1 Answer

3 votes

Answer:

49

Explanation:

To find the smallest and largest possible x-values of the endpoint on the x-axis, determine the equations of the lines that pass through point A and the endpoints of line segment PQ, then substitute y = 0 into each equation and solve for x.

Equation of line AP

Find the slope of the line that passes through point A and point P:


\textsf{slope}\:(m)=(y_A-y_P)/(x_A-x_P)=(24-4)/(20-0)=(20)/(20)=1

Substitute the found slope and one of the points into the slope-point formula to create an equation for line AP:


\implies y-y_A=m(x-x_A)


\implies y-24=1(x-20)


\implies y-24=x-20


\implies y=x+4

To find the point at which the line intersects the x-axis, substitute y = 0 into the found equation:


\implies 0=x+4


\implies x=-4

Equation of line AQ

Find the slope of the line that passes through point A and point Q:


\textsf{slope}\:(m)=(y_A-y_Q)/(x_A-x_Q)=(24-4)/(20-40)=(20)/(-20)=-1

Substitute the found slope and one of the points into the slope-point formula to create an equation for line AQ:


\implies y-y_A=m(x-x_A)


\implies y-24=-1(x-20)


\implies y-24=-x+20


\implies y=-x+44

To find the point at which the line intersects the x-axis, substitute y = 0 into the found equation:


\implies 0=-x+44


\implies x=44

Therefore, the set of x-values for the other endpoint is -4 ≤ x ≤ 44.

An integer is a whole number that can be positive, negative, or zero.

As the x-value of the endpoint is an integer, it can take the value of all integers in the set [-4, 44].

Therefore, there are 49 line segments with one endpoint A (20, 24) and another endpoint on the x-axis which have a common point with the line segment PQ.

Find the number of line segments with one endpoint A(20,24) and another endpoint on-example-1
User ARW
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