Question

What is the value of c such that x^2+14x+c is a perfect-square trinomial?

a
98
b
49
c
7
d
196

Answer 1

Answer: 49

Step-by-step explanation:

a=1 ,b=14, c=?

b^2-4ac =0

(14)^2-4(1)(c)=0

196-4c=0

196=4c

c=49

Check:

(x)^2+2(x)(7)+(7)^2

x^2+14x+49

(x+7)^2