Question

Consider the following intermediate chemical equations.

C(s) + O2(g) → CO(g)
CO(g) + O₂(g) → CO₂(g)
How will oxygen appear in the final chemical equation?
O2(g) as a product
O2(g) as a reactant
OO(g) as a product
20(g) as a reactant

Answer 1

Answer: The correct answer is: O2(g) as a reactant.

Explanation: In the final chemical equation, oxygen will appear as O2(g) as a reactant.

The first intermediate chemical equation represents the combustion of carbon to form carbon monoxide:

C(s) + O2(g) → CO(g)

The second intermediate chemical equation represents the further oxidation of carbon monoxide to form carbon dioxide:

CO(g) + O₂(g) → CO₂(g)

Combining these two intermediate reactions, we get the overall reaction:

C(s) + O2(g) → CO(g)

CO(g) + O₂(g) → CO₂(g)

C(s) + 2O2(g) → CO₂(g)

In this final chemical equation, oxygen appears as O2(g) as a reactant, as it is consumed in the reaction to form carbon dioxide. The other options, O2(g) as a product, OO(g) as a product, and 20(g) as a reactant, are not valid representations of oxygen in the final chemical equation.

Answer 2

O2(g) as a reactant

Step-by-step explanation:

as oxygen is reacting with co