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What is the solution to the system of equations?
x-y+2z=9
3x+y=z=2
2x-y+z=8

1 Answer

2 votes

Answer:

x=8/7, y=-25/7, z=15/7

Explanation:

x-y+2z=9 ==> equation 1

3x+y=z=2 ==> equation 2

2x-y+z=8 ==> equation 3

3x+y+z=2

+ (2x-y+z=8)

3x+2x + y+(-y) + z+z = 2+8 ==> add equation 2 and 3 to eliminate y

5x + 2z = 10 ==> equation 4

x-y+2z=9

- (2x-y+z=8)

x - 2x + (-y)-(-y) + 2z-z = 9-8 ==> subtract equation 1 and 3 to eliminate y

-x + 0 + z = 1 ==> Let's say -y=a. (-y)-(-y) = a-a = 0.

(-x + z = 1)*2 ==> multiply by 2 to get z to become 2z

-2x + 2z = 2 ==> equation 5

5x + 2z = 10

- (-2x + 2z = 2)

5x-(-2x) + 2z-2z = 10-2 ==> subtract equation 4 and 5 to solve for x

5x+2x = 8

7x = 8 ==> divide both sides by 7 to isolate x

x = 8/7

-2(8/7) + 2z = 2 ==> plugin x into equation 5 to solve for z

-16/7 + 2z = 2 ==> simplify

(-16/7 + 2z = 2)*7 ==> multiply the equation by 7 to eliminate fractions

-16 + 14z = 14

14z = 30 ==> add 16 on both sides to isolate z

z = 30/14 ==> divide each side by 14

z = 15/7 ==> simplify

2(8/7)-y+(15/7)=8 ==> plugin x = 8/7 and z = 15/7 into equation 3

16/7 - y + 15/7 = 8

(16/7 + 15/7 - y = 8)*7 ==> multiply the equation by 7 to remove fractions

16 + 15 - 7y = 56

31 - 7y = 56

-7y = 25 ==> subtract 31 on both sides to isolate y

7y = -25

y = -25/7

Answer: (x=8/7, y=15/7, z=-25/7)

User Marcelo A
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