154k views
2 votes
Does asymptote mean undefined?

User Shylo Hana
by
8.2k points

1 Answer

6 votes
A vertical asymptote does mean undefined in a way, but asymptotes act like limits to a function, meaning a function will never intercept them.

For example:

Take the function: f(x)=1/x^2-9

A vertical asymptote occurs when the domain cannot be a certain value, thus the function cannot cross the line for that value because there is no input nor output. So, in a way, they can be considered undefined.

In the example, we must set the denominator equal to 0 in the rational function, since a number divided by 0 is undefined. We are trying to figure out what value for x creates a denominator of 0, and that will be a vertical asymptote.

x^2-9 is the denominator terms

x^2-9=0

We must solve for x to figure out what domain value for x equals a denominator of 0:

Add 9 to both sides:

x^2=9

Take the positive and negative square roots of 9:

±√x^2=±√9

x=3, -3

So, our vertical asymptotes in this example are the lines x=3 and x=-3



This is because 1/(3)^2-9=1/0 and 1/(-3)^2-9=1/0, both of which are undefined.
User Jubnzv
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories