Question

4.) Based on the following data, what is the standard Gibbs free energy of formation of the chloride ion at 298 K?

(R = 8.314 J/(K · mol))
PbCl2(s) → Pb2+(aq) + 2Cl–(aq);
Ksp = 1.7 × 10–5

∆G°f (kJ/mol) at 298 K
Pb2+(aq) –24.4
PbCl2(s) –314.1

Answer 1

Step-by-step explanation:

Based on the following data, what is the standard Gibbs free energy of formation of the sulfate ion at 298 K? (R = 8.31 J/(K ∙mol))

PbSO4(s) Pb2+(aq) + SO42–(aq); Ksp = 1.7 × 10–8

Substance ΔG°f (kJ/mol) at 298 K

Pb2+(aq)

–24.4

PbSO4(s)

–813.0

–788.6 kJ/mol

–793.1 kJ/mol

–837.4 kJ/mol

–744.3 kJ/mol

832.9 kJ/mol