Question

A worker drives a .500 kg spike into a rail tie with a 2.50 kg sledgehammer. the hammer hits the spike with a speed of 65 m/s. if one third of the hammers kinetic energy is converted to the internal energy of the hammer and spike how much does the total internal energy increase?

dang, someone help me and explain this pleasseeee!!

Answer 1

Step-by-step explanation:

To find the increase in total internal energy, we first need to find the kinetic energy of the sledgehammer before it hits the spike. We can use the formula:

KE = (1/2) * m * v^2

where KE is the kinetic energy, m is the mass, and v is the velocity.

Plugging in the values, we get:

KE = (1/2) * 2.50 kg * (65 m/s)^2

KE = (1/2) * 2.50 kg * 4225 m^2/s^2

KE = 5212.5 J

Next, we need to find the amount of energy that is converted to internal energy. Since one third of the kinetic energy is converted to internal energy, we can multiply the kinetic energy by 1/3 to find this value:

E = 1/3 * 5212.5 J

E = 1737.5 J

Finally, we need to find the total internal energy increase by adding the energy converted to internal energy to the initial internal energy of the hammer and spike. Since the initial internal energy is zero, the total internal energy increase is simply the energy converted to internal energy:

Total internal energy increase = 1737.5 J

Therefore, the total internal energy increases by 1737.5 J when the sledgehammer hits the spike.