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What is (3x^3 −2x^2 +6x−1) subtracted from the sum
of (2x^3 −3x+2) and (5x^2 +4x−6)?

User DonQ
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1 Answer

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Answer:

the result of subtracting (3x^3 −2x^2 +6x−1) from the sum of (2x^3 −3x+2) and (5x^2 +4x−6) is −x^3 +3x^2 +7x−5.

Explanation:

To find the result of subtracting (3x^3 −2x^2 +6x−1) from the sum of (2x^3 −3x+2) and (5x^2 +4x−6), we can first add the two given expressions to find the sum, and then subtract the third expression from that sum.

The sum of (2x^3 −3x+2) and (5x^2 +4x−6) is:

(2x^3 −3x+2) + (5x^2 +4x−6) = 2x^3 +5x^2 −3x+4x −6 = 2x^3 +5x^2 +x−6

Subtracting (3x^3 −2x^2 +6x−1) from this sum gives us:

(2x^3 +5x^2 +x−6) − (3x^3 −2x^2 +6x−1) = (2x^3 −3x^3) + (5x^2 −2x^2) + (x+6x) − (−1−6) = −x^3 +3x^2 +7x−5

Therefore, the result of subtracting (3x^3 −2x^2 +6x−1) from the sum of (2x^3 −3x+2) and (5x^2 +4x−6) is −x^3 +3x^2 +7x−5.

User Plamen Nikolov
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