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3 votes
Let K=
20^(20).Suppose that
(20^(k) )/(k^(20) ) =20^(n).find the largest power of 20 that divides n?

User Samsam
by
8.3k points

1 Answer

2 votes

Answer:

20^2 = 400, the 2nd power of 20

Explanation:

Given that k=20^20 and 20^k/k^20 = 20^n, you want the largest power of 20 that divides n.

Logarithms

Taking the base-20 logarithm of both equations, we have ...


log_20(k)=\log_(20){20^(20)}\ \Longrightarrow\ log_20(k)=20\\\\\log_(20){(20^k)/(k^(20))}=log_20(20^n)\ \Longrightarrow\ k-20log_20(k)=n

Substituting for k and log(k), we get ...


20^(20) -20\cdot20=n\\\\20^2(20^(18)-1)=n

This shows us the largest power of 20 that is a factor of n is 20².

User Cross Vander
by
8.0k points

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