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A semi-circle has an area of 50 m². Find the perimeter of the semi-circle. Give your answer correct to one decimal place.​

1 Answer

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Answer:

29.0 m

Explanation:


\boxed{\begin{minipage}{4cm}\underline{Area of a semicircle}\\\\$A=(1)/(2)\pi r^2$\\\\where:\\\phantom{ww}$\bullet$ $r$ is the radius\\ \end{minipage}}

Given the area of the semicircle is 50 m², substitute this into the formula and rearrange to isolate r:


\begin{aligned}\implies(1)/(2)\pi r^2&=50\\\pi r^2 & = 100\\r^2 & = (100)/(\pi)\\r&=\sqrt{(100)/(\pi)}\end{aligned}

The perimeter of a semicircle is the sum of the diameter of the circle and half its circumference.

  • Diameter of a circle = 2r
  • Circumference of a circle = 2πr

Therefore:


\begin{aligned}\textsf{Perimeter of a semicircle}&=2r+\pi r\\&=r(2+\pi)\\&=\sqrt{(100)/(\pi)}(2+\pi)\\&=29.0083301...\end{aligned}

Therefore, the perimeter of the semicircle is 29.0 m (1 d.p.).

User Duncan Krebs
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