158k views
0 votes
A semi-circle has an area of 50 m². Find the perimeter of the semi-circle. Give your answer correct to one decimal place.​

1 Answer

2 votes

Answer:

29.0 m

Explanation:


\boxed{\begin{minipage}{4cm}\underline{Area of a semicircle}\\\\$A=(1)/(2)\pi r^2$\\\\where:\\\phantom{ww}$\bullet$ $r$ is the radius\\ \end{minipage}}

Given the area of the semicircle is 50 m², substitute this into the formula and rearrange to isolate r:


\begin{aligned}\implies(1)/(2)\pi r^2&=50\\\pi r^2 & = 100\\r^2 & = (100)/(\pi)\\r&=\sqrt{(100)/(\pi)}\end{aligned}

The perimeter of a semicircle is the sum of the diameter of the circle and half its circumference.

  • Diameter of a circle = 2r
  • Circumference of a circle = 2πr

Therefore:


\begin{aligned}\textsf{Perimeter of a semicircle}&=2r+\pi r\\&=r(2+\pi)\\&=\sqrt{(100)/(\pi)}(2+\pi)\\&=29.0083301...\end{aligned}

Therefore, the perimeter of the semicircle is 29.0 m (1 d.p.).

User Duncan Krebs
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories