Question

1.
What is the molarity of a 3.6 L solution with 104 g of sucrose?

Answer 1

.084 M

Step-by-step explanation:

Molar mass of sucrose = 342.3

The formula to find molarity is moles of solute / liters of solution

Since we need to turn grams to moles for this equation we do 104 / 342.3 = 0.304

Now we can use the equation listed above. .304 / 3.6 = 0.084 M